Matematică
andreia17
2015-11-14 08:51:00
a) [(9/28+7/1)+(4/7-1/28)]×7=? b) {1/7+[3/7-(5/28-5/84)]+1/21}:1/7=?
Răspunsuri la întrebare
nicoletascutar
2015-11-14 11:10:37

A) [(9/28+196/28)+(16/28-1/28)]*7= =(205/28+15/28)*7= =220/28*7= =220/4= =55 B) ={1/7+[3/7-(15/84-5/84)]+1/21}*7= ={1/7+[3/7-10/84]+1/21}*7= ={1/7+[3/7-5/42]+1/21}*7= ={1/7+[18/42-5/42]+1/21}*7= ={1/7+13/42+1/21}*7= ={6/42+13/42+2/42}*7= =21/42*7= =21/6= =7/2= =3,5

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