Matematică
crstinamaresi77
2015-11-18 17:02:00
Compara numerele a= 8^22 : 2^44 si b= (3^15 × 3^5 : 27^6 - 6)^11
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lucas1
2015-11-18 22:17:55

[latex]a=(2^3)^{22}:2^{44}=2^{66}:2^{44}=2^{22}=(2^2)^11=4^{11}[/latex] [latex]b=[3^{20}:(3^3)^6-6]^{11}=(3^{20}:3^{18}-6)^{11}=(3^2-6)^{11}=3^{11}[/latex] [latex]4^{11}>3^{11}[/latex] [latex]oxed{a>b}[/latex]

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