Matematică
giurascuionela
2015-11-19 11:59:15
Sa se calculeze: 5√18+√12-3√20+√72+√45, 8√12-3√27+√108, 3*(√20+√45)-√125
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dudu14
2015-11-19 14:17:31

[latex] 5 sqrt{18} + sqrt{12} -3 sqrt{20} + sqrt{72} + sqrt{45} = 5 cdot 3 sqrt{2} + 2 sqrt{3} -3 cdot 2 sqrt{5} + 6 sqrt{2} + 3 sqrt{5} = 15 sqrt{2} + 2 sqrt{3} -6 sqrt{5} + 6 sqrt{2} + 3 sqrt{5} = 21 sqrt{2} + 2 sqrt{3} -3 sqrt{3} [/latex] [latex] 8 sqrt{12} -3 sqrt{27} + sqrt{108} = 8 cdot 2 sqrt{3} - 3 cdot 3 sqrt{3} + 6 sqrt{3} = 16 sqrt{3} - 9 sqrt{3} + 6 sqrt{3} = 13 sqrt{3} [/latex] [latex] 3 cdot ( 2 sqrt{5} + 3 sqrt{5} ) - sqrt {125} = 3 cdot 5 sqrt {5} - 5 sqrt{5} = 10 sqrt{5} [/latex]

miikaelaangel
2015-11-19 14:18:46

=5*3√2+2√3-3*2√5+6√2+3√5= =15√2+2√3-6√5+6√2+3√5= =21√2+2√3-3√5 =8*2√3-3*3√3+6√3= =16√3-9√3+6√3= =13√3 =3*(2√5+3√5)-5√5= =3*5√5-5√5= =15√5-5√5= =10√5

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