Matematică
draganlarisa24
2015-11-20 20:55:45
[latex]Sa~se~calculeze: \ lg__{24} 2~in~functie~de~c=log__{24}3[/latex]
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poreclaadrianma
2015-11-21 01:14:30

[latex]c=log_ig{24}3\\log_ig{24}2 = dfrac{log_ig{3}2}{log_ig{3}24} = dfrac{log_ig{3}2}{dfrac{1}{log_ig{24}3}} = dfrac{log_ig{3}2}{dfrac{1}{c}} = ccdot log_ig{3}2 \ \ \ Rightarrowoxed{ log_ig{24}2 = ccdot log_ig{3}2}[/latex]

diananea6
2015-11-21 01:15:45

[latex]displaystyle Folosim~identitatea ~oxed{log_ab cdot log_bc= log_ac}.\ \ log_{24}2= log_{24}3 cdot log_32=c cdot log_32. \ \ [/latex]

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