[latex] x^{3} + 3 x^{2} * frac{1}{x} + 3x* frac{1}{ x^{2} } + frac{1}{ x^{3} } =64 x^{3} + 3 x } + 3* frac{1}{ x } + frac{1}{ x^{3} } =64[/latex]· Dupa asta, dai factor comun pe 3 asa:  [latex] x^{3} + frac{1}{x^{3} } + 3(x+ frac{1}{x} )=64[/latex] Dar tu stii ca   [latex]x+ frac{1}{x} =4[/latex] Rezulta ca   [latex] x^{3} + frac{1}{ x^{3} } +3*4=64 x^{3} + frac{1}{ x^{3} } +12=64 x^{3} + frac{1}{ x^{3} } =64-12 x^{3} + frac{1}{ x^{3} } =52[/latex] Sper ca ai inteles.