Matematică
anaalexandra2005
2015-11-25 15:27:00
(-2)^3 ×(-4)^2÷(-2)^5 calculati
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maria3loredana
2015-11-25 19:19:04

(-2)^3 * (-4)^2 : (-2)^5 = (-2)^3 : (-2)^5 * (-4)^2 = (-2)^(3-5) * 4^2 = (-2)^(-2) * 4^2 = 4^2 : 2^2 = 16:4 = 4

andradabreazu
2015-11-25 19:20:19

(-1)^(3+2+5) * 2^(3+2*2-5)=+2^(3-1)=2²=4 as simple as that, desigur!

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