Matematică
Tony456Bobe
2015-11-08 15:08:15
Efectuați a.(3^2-2^3):(6^2-7×5)= b.(4^3-23^0):3^2+2^2×8= c.(2^2-3)^100+5:[3^2-4×(3^1-3^0)]×1^2013= d.21^2-2×{11^2+21:(2-1)+2×[1+2^3×(1+2)+2^4-2^1]} CA ROG REPEDE!!
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flvvv
2015-11-08 15:54:49

a) (9-8):(36-35)=1:1=1 b) (64-1):9+4×8=63:9+32=7+32=39 c) (4-3)^100+5:[9-4×(3-1)]×1=1+5:[9-4×2]×1=1+5:[9-8]×1=1+5:1×1=1+5×1=1+5=6 d) 441-2×{121+21:1+2×[1+8×3+16-2]} 441-2×{121+21+2×[1+24+14]} 441-2×{142+2×39} 441-2×{142+78}=441-2×220=441-440=1

chirirlicimihai
2015-11-08 15:56:04

Pai:a.(9-8):(36-35)= 1:1=1 b.(64-1):9+4×8= 63:9+32= 7+32=39 c. (4-3)^100+5:[9-4×(3-1)]×1 =1+5:[9-4×2]×1 =1+5:[9-8]×1 =1+5:1×1 =1+5×1 =1+5 =6 Si ultimul:d. 441-2×{121+21:1+2×[1+8×3+16-2]} 441-2×{121+21+2×[1+24+14]} 441-2×{142+2×39} 441-2×{142+78} =441-2×220 =441-440 =1 Pa si succes!!!!!!

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